NCERT Solutions
Class 12 Maths
Relations and Functions

Ex. 1.1 Q3
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Let A = {1, 2, 3, 4, 5, 6}.
A relation R is defined on set A as: R = {(a, b): b = a + 1}
So, R = {(1, 2), (2, 3), (3, 4), (4, 5), (5, 6)}
we can find (a, a) ∉ R, where a ∈ A.
For instance,
(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6) ∉ R
So, R is not reflexive.
It can be observed that (1, 2) ∈ R, but (2, 1) ∉ R.
So, R is not symmetric.
Now, (1, 2), (2, 3) ∈ R
But, (1, 3) ∉ R
So, R is not transitive
Hence, R is neither reflexive, nor symmetric, nor transitive.